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Question

Physics Question on laws of motion

An object is kept on a smooth inclined plane of 11 in l.l. The horizontal acceleration to be imparted to the inclined plane so that the object is stationary relative to incline is

A

gl21 g\sqrt{l^{2}-1}

B

g(l21) g(l^{2}-1)

C

gl21\frac{g}{\sqrt{l^{2}-1}}

D

gl21\frac{g}{l^{2}-1}

Answer

gl21\frac{g}{\sqrt{l^{2}-1}}

Explanation

Solution

Here, sinθ=1l\sin \theta=\frac{1}{l}
When horizontal acceleration is imparted to the inclined plane, then a pseudo acceleration acts on the object. For the object to remain stationary relative to the incline, we have


a=gtanθ=g1l21a=g \tan \theta=g \frac{1}{\sqrt{l^{2}-1}}
or a=gl21a=\frac{g}{\sqrt{l^{2}-1}}