Question

An object is at a temperature of . At what temperature would it radiate energy twice as fast? The temperature of the surroundings may be assumed to be negligible

• A.
• B.
• C.
• D. 800 K

Answer 1

Answer: (D)

800 K

Answer 2

$\frac { E _ { 2 } } { E _ { 1 } } = \left( \frac { T _ { 2 } } { T _ { 1 } } \right) ^ { 4 }$⇒ $= \left( \frac { 673 } { T } \right) ^ { 4 }$

⇒ $T = 2 ^ { 1 / 4 } \times 673$ = 800K.