Question

An n-p-n transistor of current gain 80 in common emitter mode gives emitter current equal to 8.1 mA. The base current is

• A. 0.1 $\mu$A
• B. 0.01 mA
• C. 0.1 mA
• D. 0.01 $\mu$A

Answer 1

Answer: (C)

0.1 mA

Answer 2

$\beta=80$
$l_{c}=8.1mA$
$\left(\frac{l_{c}}{l_{b}}\right) =80\left(l_{e}=l_{b}+l_{c}\right)$
$\left(\frac{l_{e-l_b}}{l_{b}}\right) =80$