Question
Question: An n – p – n transistor circuit has a = 0.985. If I<sub>c</sub> = 2mA, then value of I<sub>b</sub> i...
An n – p – n transistor circuit has a = 0.985. If Ic = 2mA, then value of Ib is –
A
0.03 mA
B
0.003 mA
C
0.66 mA
D
0.015 mA
Answer
0.03 mA
Explanation
Solution
a = IeIc = Ic+IbIc= 0.985
Ic = 0.985 (Ic + Ib)
Ic = 0.985 Ic + 0.985 Ib
0.985 Ib = 0.015 Ic = 0.015 × 2 mA
Ib = 0.9850.015×2= 0.03 mA
Ib ≈0.03 mA