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Question: An n – p – n transistor circuit has a = 0.985. If I<sub>c</sub> = 2mA, then value of I<sub>b</sub> i...

An n – p – n transistor circuit has a = 0.985. If Ic = 2mA, then value of Ib is –

A

0.03 mA

B

0.003 mA

C

0.66 mA

D

0.015 mA

Answer

0.03 mA

Explanation

Solution

a = IcIe\frac{I_{c}}{I_{e}} = IcIc+Ib\frac{I_{c}}{I_{c} + I_{b}}= 0.985

Ic = 0.985 (Ic + Ib)

Ic = 0.985 Ic + 0.985 Ib

0.985 Ib = 0.015 Ic = 0.015 × 2 mA

Ib = 0.015×20.985\frac{0.015 \times 2}{0.985}= 0.03 mA

Ib \approx0.03 mA