Solveeit Logo
Login

Question

Question: An \(B = 1.2 \mathrm {~Wb} / \mathrm { m } ^ { 2 }\) with a speed of \(2.6 \times 10 ^ { 7 } \mathr...

An B=1.2 Wb/m2B = 1.2 \mathrm {~Wb} / \mathrm { m } ^ { 2 } with a speed of

2.6×107 m/sec2.6 \times 10 ^ { 7 } \mathrm {~m} / \mathrm { sec }. The period of revolution of the α−\alpha -particle is

A

1.1×10−5sec1.1 \times 10 ^ { - 5 } \mathrm { sec }

B

1.1×10−6sec1.1 \times 10 ^ { - 6 } \mathrm { sec }

C

1.1×10−7sec1.1 \times 10 ^ { - 7 } \mathrm { sec }

D

1.1×10−8sec1.1 \times 10 ^ { - 8 } \mathrm { sec }

Answer

1.1×10−7sec1.1 \times 10 ^ { - 7 } \mathrm { sec }

Explanation

Solution

T=2πmqB=2πrv=2×3.14×0.452.6×107=1.08×10−7secT = \frac { 2 \pi m } { q B } = \frac { 2 \pi r } { v } = \frac { 2 \times 3.14 \times 0.45 } { 2.6 \times 10 ^ { 7 } } = 1.08 \times 10 ^ { - 7 } \mathrm { sec }