Question

An LPG cylinder, containing $15\, kg$ butane at $27^{\circ} C$ and $10\, atm$ pressure, is leaking. After one day, its pressure decreased to 8 atm. The quantity of gas leaked is

• A. 1 kg
• B. 2 kg
• C. 3 kg
• D. 4 kg

Answer 1

Answer: (C)

3 kg

Answer 2

According to question- $T, V$ are constant, hence from ideal gas equation, we have. $\frac{p_{1}}{p_{2}} =\frac{n_{1}}{n_{2}}=\frac{w_{1}}{w_{2}}$ $\frac{10}{8} =\frac{15}{w_{2}}$ or $w_{2} =12\, kg$ Hence, gas leaked $=15-12=3\, kg$