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Question: An LCR series circuit is connected to an external e.m.f. \(e = 200\sin 100\pi t\). The values of the...

An LCR series circuit is connected to an external e.m.f. e=200sin100πte = 200\sin 100\pi t. The values of the capacitance and resistance in the circuit are 2μF2\mu F and 100Ω100\Omega respectively. The amplitude of the current in the circuit will be maximum when the inductance is

A

100 Henry

B

50/π250/\pi^{2} Henry

C

100 π Henry

D

100×π2100 \times \pi^{2}Henry

Answer

50/π250/\pi^{2} Henry

Explanation

Solution

Current will be maximum in resonance i.e. XL = X

100π×L=1100π×2×106100\pi \times L = \frac{1}{100\pi \times 2 \times 10^{- 6}}L=50π2Henry.L = \frac{50}{\pi^{2}}Henry.