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Question

Physics Question on Alternating current

An LCR series circuit containing a resistance of 120Ω120\Omega has angular resonance frequency 4×1054\times 10^5 rad S1S^{-1}. At resonance the voltage across resistance and inductance are 60V and 40V respectively. Then the values of L agd C are respectively

A

0.2mH,1/32μF0.2\,mH ,1/32\,\mu F

B

0.4mH,1/16μF0.4\,mH ,1/16\,\mu F

C

0.2mH,1/16μF0.2\,mH ,1/16\,\mu F

D

0.4mH,1/32μF0.4\,mH ,1/32\,\mu F

Answer

0.2mH,1/32μF0.2\,mH ,1/32\,\mu F

Explanation

Solution

At resonance i=VR=VLXL;XL=ωLω=1LCi=\frac{V}{R}=\frac{V_L}{X_L};X_L=\omega \,L\omega =\frac{1}{\sqrt{LC}}