Question

An $LCR$ circuit contains $R = 50 \, \Omega , L = 1 \, mH$ and $C = 0.1 \mu F$ . The impedence of the circuit will be minimum for a frequency of

• A. $\frac{10^5}{2 \pi} H z$
• B. $\frac{10^6}{2 \pi} H z$
• C. $2 \pi \times 10^5 H z$
• D. $2 \pi \times 10^6 H z$

Answer 1

Answer: (A)

$\frac{10^5}{2 \pi} H z$

Answer 2

Impedance of $L-C-R$ circuit will be minimum for a resonant frequency so,
$v_{0} =\frac{1}{2 \pi \sqrt{L C}}$
$=\frac{1}{2 \pi \sqrt{1 \times 10^{-3} \times 0.1 \times 10^{-6}}}$
$=\frac{10^{5}}{2 \pi} Hz$