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Question

Physics Question on Alternating current

An LCLC circuit contains a 20mH20\,mH inductor and a 50μF50\, \mu F capacitor with an initial charge of 10mC10\, mC. The resistance of the circuit is negligible. Let the instant at which the circuit which is closed be t=0t = 0. At what time the energy stored is completely magnetic?

A

t=0t = 0

B

t=1.54mst= 1.54 \,ms

C

t=3.14mst= 3.14 \,ms

D

t=6.28mst= 6.28 \,ms

Answer

t=1.54mst= 1.54 \,ms

Explanation

Solution

At time t=T4t=\frac{T}{4}, energy stored is completely magnetic. \therefore Time t=T4=2πLC4t=π20×103×50×1062t = \frac{T}{4}=\frac{2\pi\sqrt{LC}}{4} \Rightarrow t=\frac{\pi\sqrt{20\times10^{-3}\times50\times10^{-6}}}{2} t=π1000×1092t=\frac{\pi\sqrt{1000\times10^{-9}}}{2} =π1×1062=\frac{\pi\sqrt{1\times10^{-6}}}{2} =1.57ms=1.57\,ms