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Question: An isosceles triangle is inscribed in the parabola y<sup>2</sup>= 4ax with its base as the line join...

An isosceles triangle is inscribed in the parabola y2= 4ax with its base as the line joining the vertex and positive end of the latus rectum of the parabola. If (at2, 2at) is the vertex of the triangle then

A

2t2– 8t + 5 = 0

B

2t2 + 8t – 5 = 0

C

2t2+ 8t + 5= 0

D

2t2– 8t – 5 = 0

Answer

2t2 + 8t – 5 = 0

Explanation

Solution