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Physics Question on Magnetism and matter

An iron rod of susceptibility 599 is subjected to a magnetising field of 1200 A m−1m^{-1}. The permeability of the material of the rod is : (μo=4π×10−7T m A−1)(\mu_o = 4\pi \times 10^{-7} T\,m\,A^{-1})

A

2.4π×10−4T m A−12.4 \pi \times 10^{-4} T\,m\,A^{-1}

B

8.0π×10−5T m A−18.0 \pi \times 10^{-5} T\,m\,A^{-1}

C

2.4π×10−5T m A−12.4 \pi \times 10^{-5} T\,m\,A^{-1}

D

2.4π×10−7T m A−12.4 \pi \times 10^{-7} T\,m\,A^{-1}

Answer

2.4π×10−4T m A−12.4 \pi \times 10^{-4} T\,m\,A^{-1}

Explanation

Solution

Given, χm=599\chi_{m}=599
Also, μr=1+χm=600\mu_{r}=1+\chi_{m}=600
We know, μ=μrμo\mu=\mu_{r}\mu_{o}
μ=600×4π×10−7\mu=600\times4\pi\times10^{-7}
μ=2400π×10−7\mu=2400\pi\times10^{-7}
μ=2.4π×10−4 T m A−1\mu=2.4\pi\times10^{-4}\,T\,m\,A^{-1}