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Question: An iron rod of length *L* and magnetic moment *M* is bent in the form of a semicircle. Now it’s magn...

An iron rod of length L and magnetic moment M is bent in the form of a semicircle. Now it’s magnetic moment will be

A

MM

B

2Mπ\frac { 2 M } { \pi }

C

Mπ\frac { M } { \pi }

D

MπM \pi

Answer

2Mπ\frac { 2 M } { \pi }

Explanation

Solution

On bending a rod it's pole strength remains unchanged where as it's magnetic moment changes

New magnetic moment M′=m(2R)=m(2Lπ)=2MπM ^ { \prime } = m ( 2 R ) = m \left( \frac { 2 L } { \pi } \right) = \frac { 2 M } { \pi }