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Question

Physics Question on laws of motion

An iron block of mass 5kg5\, kg is kept on a trolley. If the trolley is being pushed with an acceleration of 5m/s5\,m / s 2 2, what will be the force of friction between the block and the trolley surface? (Take the coefficient of static friction between the block and the trolley surface to be 0,80,8).

A

Zero

B

5 N

C

4 N

D

25 N

Answer

25 N

Explanation

Solution

Applied force =m×a=5×5=25=m \times a=5 \times 5=25 Limiting friction =μmg=0.8×5×10=40=\mu\, m g=0.8 \times 5 \times 10=40 For the given condition applied force is very smaller than limiting friction \therefore Static friction on a body == applied force =ma=m a =5×5=25N=5 \times 5=25 \,N