Question
Question: An intrinsic semiconductor has a resistivity of \(0.50\Omega\) m at room temperature. Find the intri...
An intrinsic semiconductor has a resistivity of 0.50Ω m at room temperature. Find the intrinsic carries concentration if the mobilities of electrons and holes are 0.39m2V−1s−1 and 0.11m2V−1s−1 respectively
A
1.2×1018m−3
B
2.5×1019m−3
C
1.9×1020m−3
D
3.1×1021m−3
Answer
2.5×1019m−3
Explanation
Solution
: here, ρ=0.50Ωm
}{\mu_{h} = 0.11m^{2}V^{- 1}s^{- 1}}$$ The resistivity of intrinsic semiconductor is $$\frac{1}{\rho} = e(n_{i}\mu_{e} + n_{i}\mu_{h})$$ Where $n_{i}$is the intrinsic carrier concentration $$\therefore n_{i} = \frac{1}{\rho e(\mu_{e} + \mu_{h})}$$ Substituting the given values, we get $$n_{i} = \frac{1}{(0.5)(1.6 \times 10^{- 19})(0.39 + 0.11)} = 2.5 \times 10^{19}m^{- 3}$$