Question
Question: An insulating pipe of cross-section area 'A' contains an electrolyte which has two types of ions, th...
An insulating pipe of cross-section area 'A' contains an electrolyte which has two types of ions, their charges being −e and +2e . A potential difference applied between the ends of the pipe results in the drifting of the two types of ions, having drift speed =v(−ve) ion and 4v(+ve) ion . Both ions have the same number per unit volume =n . The current flowing through the pipe is.
(A) nev2A
(B) nev4A
(C) 5nev2A
(D) 4nev2A
Solution
First find the total current in the pipe due to both the given charges then use the formula to find the current using drift velocity, area of cross-section, charge, and number of ions per unit volume. We will get our required current in the pipe.
I=neA×Vd
Where, n is the number of ions per unit volume. A is the area of cross-section. e is the charge. Vd is the drift velocity.
Complete Step By Step Answer:
We have been given a pipe of cross section ‘A’ inside which there is an electrolyte which has two charges −e and +2e their respective drift velocity are, v(−ve) and 4v(+ve) .
The total current flowing through the pipe will be due to both the charges −e and +2e
⇒Itotal=I+2e−I−e
I+2e is due to the positive ion moving along the field.
I−e is due to the negative ion moving opposite to the field.
The equation for the relationship between current and drift velocity is
I=neA×Vd
Where, n is the number of ions per unit volume. A is the area of cross-section. e is the charge. Vd is the drift velocity.
Since both ions have the same number per unit volume , then the current will be
⇒Itotal=n×(2e)×A×4v−(n×(−e)×A×(−v))
⇒Itotal=nev2A
Hence option A) nev2A is the correct option.
Note:
The average velocity gained by free electrons in a conductor under the effect of an electric field applied across the conductor is known as drift velocity. If an electric field is applied to a solution, the positive ions will migrate inside the solution (following the field), whereas the negative ions will move in the opposite direction.