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Question

Physics Question on Electric Power

An installation consisting of an electric motor driving a water pump left 75L75\, L of water per second to a height of 4.7m4.7\, m. If the motor consumes a power of 5kW5\, kW, then the efficiency of the installation is

A

0.39

B

0.69

C

0.93

D

0.96

Answer

0.69

Explanation

Solution

Power consumed by the motor =5kW=5\, kW
=5×103W=5 \times 10^{3} W
=5000W=5000\, W
Power used in lifting the water
mght-\frac{m g h}{t}
=7.5×9.8×4.7=7.5 \times 9.8 \times 4.7
=3454.5kW=3454.5\, kW
Efficiency = Power used  Power consumed ×100%= \frac{\text { Power used }}{\text { Power consumed }} \times 100 \%
=3454.55000×100=69%=\frac{3454.5}{5000} \times 100=69 \%