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Question: An insect jumps from ball \(A\) onto ball \(B\), which are suspended from inextensible light strings...

An insect jumps from ball AA onto ball BB, which are suspended from inextensible light strings each of length L=8 cmL=8\text{ cm}. The mass of each ball and insect is the same. What should be the minimum relative velocity (in ms1m{{s}^{-1}}) of jump of insect w.r.t. ball AA, if both the balls manage to complete the full circle?

A. 99
B. 88
C. 1010
D. 2020

Explanation

Solution

To solve this problem we will use the concept of conservation of linear momentum because no external force acts on the system. We have considered the insect and both the balls as a system in this case whose linear momentum will be conserved. Also, we need to recall the velocity required by an object to complete a circle when it travels in a circular motion.

Complete step-by-step answer:
Let us assume that the insect jumps from ball AA onto ball BB with a velocity uu and the mass of each ball and insect be mm. Since, no external force is applied on the system, hence the linear momentum of the system will be conserved. If the insect jumps from ball AA onto ball BB with a velocity uu then it will impart the same velocity uu on the ball AA in the opposite direction. On conserving the momentum considering that the system was initially at rest, we get:
0=mu+2mv 2mv=mu 2v=u v=u2 \begin{aligned} & 0=-mu+2mv \\\ & \Rightarrow 2mv=mu \\\ & \Rightarrow 2v=u \\\ & \Rightarrow v=\dfrac{u}{2} \\\ \end{aligned}
Thus, ball BB will have a velocity of u2\dfrac{u}{2} and if the balls have to complete a full circle, then the ball with lower velocity must at least fulfill the condition for completing full circle. To complete full circle:
u2=5gl u2=5×10×0.08 u2=2 u=4 \begin{aligned} & \dfrac{u}{2}=\sqrt{5gl} \\\ & \Rightarrow \dfrac{u}{2}=\sqrt{5\times 10\times 0.08} \\\ & \Rightarrow \dfrac{u}{2}=2 \\\ & \Rightarrow u=4 \\\ \end{aligned}
The minimum relative velocity will be:
urel=u2u1 urel=u(u) urel=u+u urel=2u urel=2×4 urel=8 ms1 \begin{aligned} & {{u}_{rel}}={{u}_{2}}-{{u}_{1}} \\\ & \Rightarrow {{u}_{rel}}=u-\left( -u \right) \\\ & \Rightarrow {{u}_{rel}}=u+u \\\ & \Rightarrow {{u}_{rel}}=2u \\\ & \Rightarrow {{u}_{rel}}=2\times 4 \\\ & \therefore {{u}_{rel}}=8\text{ m}{{\text{s}}^{-1}} \\\ \end{aligned}

So, the correct answer is “Option B”.

Note: We applied the condition for an object to complete a full circle only on the ball with a lower velocity i.e., ball BB because the other ball has a higher velocity and can definitely complete a full circle if the ball with a lower velocity can do so. Our solution would have been incorrect if we used the condition for ball AA.