Question

An infinite conducting sheet of charge has surface charge density s. The distance between two points is r. The potential difference (v_A – v_B) between these points is –

• A. $\frac{\sigma r}{2\varepsilon_{0}}$
• B. $\frac{\sigma r}{\varepsilon_{0}}$
• C. $\frac{\sigma}{\varepsilon_{0}r}$
• D. $\frac{\sigma}{2\varepsilon_{0}r}$

Answer 1

Answer: (A)

$\frac{\sigma r}{2\varepsilon_{0}}$

Answer 2

V_A – V_B = $\int _ { \mathrm { a } } ^ { \mathrm { b } } \mathrm { E } \cdot \mathrm { dr }$ = E (b – a) =