Question
Physics Question on Alternating current
An inductor of inductance L and resistor of resistance R are joined in series and connected by a source of frequency ω. Power dissipated in the circuit is
A
(VR2+ω2L2)
B
(R2+ω2L2)V2R
C
(R2+ω2L2V)
D
V2R2+ω2L2
Answer
(R2+ω2L2)V2R
Explanation
Solution
P = Vicosϕ + V (ZV)(ZR) = Z2V2R = (R2+ω2L2)V2R