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Question

Physics Question on Alternating current

An inductor of inductance L and resistor of resistance R are joined in series and connected by a source of frequency ω\omega. Power dissipated in the circuit is

A

(R2+ω2L2V) \bigg( \frac{ R^2 + \omega^2 \, L^2 }{ V} \bigg)

B

V2R(R2+ω2L2)\frac{ V^2 \, R }{ (R^2 + \omega^2 \, L^2 )}

C

(VR2+ω2L2) \bigg( \frac{ V}{ R^2 + \omega^2 \, L^2 } \bigg)

D

R2+ω2L2V2\frac{ \sqrt{ R^2 + \omega^2 \, L^2 }}{ V^2 }

Answer

V2R(R2+ω2L2)\frac{ V^2 \, R }{ (R^2 + \omega^2 \, L^2 )}

Explanation

Solution

P = VicosϕV i \cos \, \phi + V (VZ)(RZ)\bigg( \frac{ V}{ Z} \bigg) \bigg( \frac{ R}{ Z} \bigg) = V2RZ2\frac{ V^2 \, R}{ Z^2 } = V2R(R2+ω2L2)\frac{ V^2 \, R}{ ( R^2 + \omega^2 \, L^2 ) }