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Question: An inductance of 1 mH a condenser of 10 μF and a resistance of 50 Ω are connected in series. The rea...

An inductance of 1 mH a condenser of 10 μF and a resistance of 50 Ω are connected in series. The reactances of inductor and condensers are same. The reactance of either of them will be

A

100 Ω

B

30 Ω

C

3.2 Ω

D

10 Ω

Answer

10 Ω

Explanation

Solution

Given ωL=1ωC\omega L = \frac{1}{\omega C} \Rightarrow ω2=1LC\omega^{2} = \frac{1}{LC}

or ω=1103×10×106=1108=104\omega = \frac{1}{\sqrt{10^{- 3} \times 10 \times 10^{- 6}}} = \frac{1}{\sqrt{10^{- 8}}} = 10^{4}

XL=ωL=104×103=10ΩX_{L} = \omega L = 10^{4} \times 10^{- 3} = 10\Omega