Question

An incompressible fluid is flowing through a vertical pipe (height h and crosssectional area 𝐴𝑜). A thin mesh, having n circular holes of area 𝐴ℎ is fixed at the bottom end of the pipe. The speed of the fluid entering the top-end of the pipe is 𝑣𝑜. The volume flow rate from an individual hole of the mesh is given by:
(g is the acceleration due to gravity)

• A. $\frac{A_0}{n}\sqrt{v^2_o+2gh}$
• B. $\frac{A_0}{n}\sqrt{v^2_o+gh}$
• C. $n(A_O-A_h)\sqrt{v^2_o+2gh}$
• D. $n(A_O-A_h)\sqrt{v^2_o+gh_o}$

Answer 1

Answer: (A)

$\frac{A_0}{n}\sqrt{v^2_o+2gh}$

Answer 2

The correct option is (A): $\frac{A_0}{n}\sqrt{v^2_o+2gh}$