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Question: An ideal transformer has 100 turns in the primary and 250 turns in the secondary. The peak value of ...

An ideal transformer has 100 turns in the primary and 250 turns in the secondary. The peak value of the ac is 28 V. The r.m.s. secondary voltage is nearest to

A

50 V

B

70 V

C

100 V

D

40 V

Answer

50 V

Explanation

Solution

NsNp=VsVp250100=Vs28/2Vs=506muV\frac{N_{s}}{N_{p}} = \frac{V_{s}}{V_{p}} \Rightarrow \frac{250}{100} = \frac{V_{s}}{28/\sqrt{2}} \Rightarrow V_{s} = 50\mspace{6mu} V