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Question: An ideal mono-atomic gas undergoes a cyclic process ABCA as shown in the figure. The ratio of heat a...

An ideal mono-atomic gas undergoes a cyclic process ABCA as shown in the figure. The ratio of heat absorbed during AB to the work done on the gas during BC is –

A

52ln2\frac{5}{2\ln 2}

B

53\frac{5}{3}

C

54ln2\frac{5}{4\ln 2}

D

56\frac{5}{6}

Answer

54ln2\frac{5}{4\ln 2}

Explanation

Solution

QAB = nCPDT = n52\frac{5}{2}R(2T0 – T0)

QBC = WBC = NR.2T0 ln 2

Ž QABWBC\frac{Q_{AB}}{W_{BC}}= 54ln2\frac{5}{4\ln 2}