Question

An ideal inductor is in turn put across 200 V, 50 H and 220 V, 100 Hz supplies. The current flowing through it in the two cases will be

• A. Equal
• B. Different
• C. Zero
• D. Infinite

Answer 1

Answer: (B)

Different

Answer 2

: The current in the inductor coil is given by

$I = \frac{V}{X_{L}} = \frac{V}{2\pi\upsilon L}$

Since frequency $\upsilon$in the two cases is different, hence the current in two cases will be different.