An ideal gas undergoes process PV1.25 = constant. Then – | PHYSICS - THERMODYNAMIC PROCESSES | SolveeIt

An ideal gas undergoes process PV^1.25 = constant. Then –

Upon increase in pressure temperature decreases

Upon increase in pressure heat is absorbed by gas

If heat is given to gas its internal energy increases

Heat is absorbed by gas if volume increasing

Answer

Heat is absorbed by gas if volume increasing

Explanation

C = R

$\left\{ \frac { 1 } { \frac { 5 } { 3 } - 1 } - \frac { 1 } { 1.25 - 1 } \right\} < 0$

̃ Temperature decreases if heat is given to gas Also,

PV = nRT =

̃ Temperature decreases with increases in volume and decrease in pressure.

Question: An ideal gas undergoes process PV<sup>1.25</sup> = constant. Then –...