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Question: An ideal gas undergoes cyclic process ABCDA as shown in given P-V diagram. The amount of work done b...

An ideal gas undergoes cyclic process ABCDA as shown in given P-V diagram. The amount of work done by the gas is

A

6 P0V0

B

–2P0V0

C

+2 P0V0

D

+4P0V0

Answer

–2P0V0

Explanation

Solution

Work done = change in pressure × change in volume =(2P0−P0)(3V0−V0)=2P0V0= \left( 2P_{0} - P_{0} \right)(3V_{0} - V_{0}) = 2P_{0}V_{0}

Since the cyclic process is anticlockwise work done by the gas is negative i.e. −2P0V0- 2P_{0}V_{0}