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Question: An ideal gas system undergoes an isothermal process, then the work done during the process is...

An ideal gas system undergoes an isothermal process, then the work done during the process is

A

nRTln V2V1\frac { V _ { 2 } } { V _ { 1 } }

B

nRTln

C

2nRTln V2V1\frac { V _ { 2 } } { V _ { 1 } }

D

2nRTln

Answer

nRTln V2V1\frac { V _ { 2 } } { V _ { 1 } }

Explanation

Solution

: Let an ideal gas goes isothermally from its initial state (P1V1)\left( P _ { 1 } V _ { 1 } \right) to the final state (P2V2)\left( P _ { 2 } V _ { 2 } \right) then work done

W=V1V2PdVW = \int _ { V _ { 1 } } ^ { V _ { 2 } } P d V

Taking PV=nRTP V = n R T or p=nRTVp = \frac { n R T } { V }

Then, W=V1V2nRTVdV=nRTV1V2dVV=nRTlnV2V1W = \int _ { V _ { 1 } } ^ { V _ { 2 } } \frac { n R T } { V } d V = n R T \int _ { V _ { 1 } } ^ { V _ { 2 } } \frac { d V } { V } = n R T \ln \frac { V _ { 2 } } { V _ { 1 } }