Question
Question: An ideal gas on heating from \[100{{K}}\] to \(109{{K}}\) shows an increase by \({{a}}\% \) in its v...
An ideal gas on heating from 100K to 109K shows an increase by a% in its volume at constant P. The value of a is …………
Solution
Ideal gas is a type of imaginary gas in which the particles are randomly moving and they do not interact with each other. They are point-like particles. Also, they obey the gas law which is the combination of Boyle’s law, Charles’ law, Gay Lussac law and Avogadro law.
Complete step by step answer:
It is given that the initial temperature, T1=100K
Final temperature, T2=109K
Percentage increase in volume, V%=a%
According to ideal gas equation, PV=nRT, where P is the pressure of the gas, V is the volume of gas, n is the number of moles of gas, R is the gas constant and T is the temperature.
Here, P,n,R are constants. Since the same ideal gas is heated, there is no change in the number of moles of the gas. Pressure is given as constant.
Thus we can write the ideal gas equation as:
V1V2=T1T2, where V1 and V2 are the initial and final volumes of gas respectively.
Substituting the values of initial and final temperatures, we get
V1V2=100109⇔V2=1.09×V1
Here, the percentage increase in the volume can be expressed as
V1V2−V1×100=a
Substituting the value of V2 in the above equation, we get
V11.09V1−V1×100=V19V1=9
Thus the percentage increase in the volume, a%=9%.
So, the value of a is 9
Note: Ideal gas equation involves four equations which explain the relationship between volume and pressure at constant number of moles and temperature (Boyle’s law); volume and temperature at constant pressure and number of moles (Charles’ law); pressure and temperature at constant number of moles and volume (Gay Lussac law); number of moles and volume at constant pressure and temperature (Avogadro law).