Question

An ideal gas occupies a volume of $2\,m^3$ at a pressure of $3 \times 10^6\, Pa$. The energy of the gas is:

• A. $3 \times 10^6 J$
• B. $10^8 J$
• C. $6 \times 10^4 J$
• D. $9 \times 10^{-6} J$

Answer 1

Answer: (D)

$9 \times 10^{-6} J$

Answer 2

Energy $= \frac{1}{2} nRT = \frac{f}{2} PV$
$= \frac{f}{2} \left(3\times10^{6}\right)\left(2\right)$
$= f\times3 \times10^{6}$
Considering gas is monoatomic i.e. $f = 3$
$E . = 9 \times10^{6} J$