Question

An ideal gas is initially at a temperature T and volume V. Its volume is increased by ∆V due to an increase in temperature ∆T, pressure remaining constant. The quantity $\delta = \frac{\Delta V}{V\Delta T}$ varies with temperature as

• A.
• B.
• C.
• D.

Answer 1

Answer: (C)

Answer 2

From ideal gas equation PV = RT …..(i)

or

$P\Delta V = R\Delta T$ …..(ii)

Dividing equation (ii) by (i) we get $\frac{\Delta V}{V} = \frac{\Delta T}{T}$

⇒ $\frac{\Delta V}{V\Delta T} = \frac{1}{T} = \delta$ (given)

∴ $\delta = \frac{1}{T}$. So the graph between δ and T will be rectangular hyperbola.