Question

An ideal gas is found to obey an additional law VP² = constant. The gas is initially at temperature T and volume V. When it expends to a volume 2 V, the temperature becomes-

• A. $\mathrm { T } / \sqrt { 2 }$
• B. 2T
• C. $2 \mathrm {~T} \sqrt { 2 }$
• D. 4 T

Answer 1

Answer: (A)

$\mathrm { T } / \sqrt { 2 }$

Answer 2

PV = nRT \ P =

VP² & wnT