Question

An ideal gas heat engine operates in Carnot cycle between 227°C and 127°C. It absorbs 6 x 104 cal of heat at higher temperature. Amount of heat converted to work is:

• A. 2.4 x 104 cal
• B. 3.6 x 104 ca
• C. 1.2 x 104 cal
• D. 6.4 x 104 cal

Answer 1

Answer: (C)

1.2 x 104 cal

Answer 2

Efficiency for a Carnot engine is e = 1 = $\frac{T_2}{T_1}$ =$\frac{1127+273}{227+273}$ =$\frac{1400}{500 }$= $\frac{1}{5}$.
e =$\frac{ Work output}{Heat input }$ is now equal to $\frac{W}{6\times 10^4}$
W=e $\times$6 $\times$104 = $\frac{1}{5}$ $\times$ 6 $\times$ 104 =1.2 $\times$104 cal.

Therefore, the correct option is (C): 1.2 x 104 cal