Question

An ideal gas heat engine operates in a Carnot cycle between $227^{\circ} C$ and $127^{\circ} C.$ It absorbs $6\, kcal$ at the higher temperature. The amount of heat (in kcal) converted into work is equal to

• A. 4.8
• B. 3.5
• C. 1.6
• D. 1.2

Answer 1

Answer: (D)

1.2

Answer 2

Efficiency of Carnot engine
$= \frac {W}{Q_1}=1- \frac {T_2}{T_1}$
$\frac {W}{6}=1- \frac {400}{500}= \frac {1}{5}$
$\Rightarrow W=\frac {6}{5}=1.2 \, k cal.$