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Question: An ideal gas at a pressure of 1 atmosphere and temperature of 27°C is compressed adiabatically until...

An ideal gas at a pressure of 1 atmosphere and temperature of 27°C is compressed adiabatically until its pressure becomes 8 times the initial pressure. Then the final temperature is (Givenγ=32)\left( \text{Given}\gamma = \frac{3}{2} \right)

A

627°C

B

527°C

C

427°C

D

327°C

Answer

327°C

Explanation

Solution

Here, P1=1atm,T1=27C=27+273=300KP_{1} = 1atm,T_{1} = 27{^\circ}C = 27 + 273 = 300K

P2=8P1,T2=?,γ=32P_{2} = 8P_{1},T_{2} = ?,\gamma = \frac{3}{2}

As change are adiabatic,

P1γ1T1γ=P2γ1T2γ\therefore{P_{1}}^{\gamma - 1}{T_{1}}^{- \gamma} = {P_{2}}^{\gamma - 1}{T_{2}}^{- \gamma}

(T2T1)γ=(P1P2)γ1\left( \frac{T_{2}}{T_{1}} \right)^{- \gamma} = \left( \frac{P_{1}}{P_{2}} \right)^{\gamma - 1}

T2=600K=(600273)C=327CT_{2} = 600K = (600 - 273){^\circ}C = 327{^\circ}C