Question

An ideal fluid of density 800kgm–3, flows smoothly through a bent pipe (as shown in figure) that tapers in cross-sectional area from a to $\frac{a}{2}$. The pressure difference between the wide and narrow sections of pipe is 4100 Pa. At wider section, the velocity of fluid is$\frac{\sqrt{x}}{6}$ ms1 for x=_______. (Given g=10 ms-2)

Answer 1

Applying Bernoulli’s theorem: $P_1 + \rho g h + \frac{1}{2} \rho v^2 = P_2 + \frac{1}{2} \rho (2v)^2$

Putting the values, $4100=800(\frac{3}{2}v^2−10)$
$⇒v=\frac{\sqrt{363}}{6}m/s$