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Question

Physics Question on Alternating current

An ideal coil of 10H10H is connected in series with a resistance of 5Ω5\, \Omega and a battery of 5V.25V. 2 second after the connection is made the current flowing in amperes in the circuit is

A

(1e)(1 - e)

B

ee

C

e1e^{-1}

D

(1e1)(1 - e^{-1})

Answer

(1e1)(1 - e^{-1})

Explanation

Solution

i=i0(1eRtL)i=i_{0}\left(1-e^{\frac{Rt}{L}}\right) =(1e1)=\left(1-e^{-1}\right)