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Question

Physics Question on LCR Circuit

An ideal coil of 10H10\, H is joined in series with a resistance of 5Ω5 \,\Omega and battery of 5V,2s5\, V,\, 2 s after joining the current flowing (in ampere) in the circuit will be

A

e1{{e}^{-1}}

B

(1e1)(1-{{e}^{-1}})

C

(1e)(1-e)

D

ee

Answer

(1e1)(1-{{e}^{-1}})

Explanation

Solution

Given, L=10H,R=5Ω,E=5VL=10\, H,\, R=5 \Omega,\, E=5\, V and t=2st=2\, s. Current in RLR-L circuit I=I0(1eRt/L)I=I_{0}\left(1-e^{-R t / L}\right) I=ER(1eRt/L)I=\frac{E}{R}\left(1-e^{-R t / L}\right) =55(1e5×2/10)=\frac{5}{5}\left(1-e^{-5 \times 2 / 10}\right) I=(1e1)I=\left(1-e^{-1}\right)