Question

An iceberg is floating partially immersed in sea water. The density of sea water is 1.03 g cm^–3 and that of ice is 0.92 g cm^–3. The approximate percentage of total volume of iceberg above the level of sea water is –

• A. 8
• B. 11
• C. 34
• D. 89

Answer 1

Answer: (B)

11

Answer 2

(V – DV) × 1.03 × g = V × 0.92 × g

$\frac{V - \Delta V}{V} = \frac{0.92}{1.03}$

$\frac { \Delta \mathrm { V } } { \mathrm { V } } = \frac { 1 - 0.92 } { 1.03 } = \frac { 0.11 } { 1.03 }$ $\frac{\Delta V}{V} \times 100 = \frac{11}{1.03} \approx 11$