Question

An ice-cube of density $900\, kg / m ^{3}$ is floating in water of density $1000\, kg / m ^{3}$. The percentage of volume: of ice-cube outside the water is :

• A. 0.2
• B. 0.35
• C. 0.1
• D. 0.25

Answer 1

Answer: (C)

0.1

Answer 2

The percentage of volume of ice-cube outside the water is $=\frac{\rho_{\text {water }}-\rho_{\text {loe }}}{\rho_{\text {water }}} \times 100$ $=\frac{1000-900}{1000} \times 100=10 \%$