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Question: An ice berg of density 900 Kg/m<sup>3</sup> is floating in water of density 1000 Kg/m<sup>3</sup>. T...

An ice berg of density 900 Kg/m3 is floating in water of density 1000 Kg/m3. The percentage of volume of ice-cube outside the water is

A

20%

B

35%

C

10%

D

25%

Answer

10%

Explanation

Solution

Let the total volume of ice-berg is V and its density is ρ. If this ice-berg floats in water with volume Vin inside it then

Vinσg=VρgV _ { i n } \sigma g = V \rho gσ=\sigma =density of water]

or

Vout V=(σρσ)=10009001000=110\frac { V _ { \text {out } } } { V } = \left( \frac { \sigma - \rho } { \sigma } \right) = \frac { 1000 - 900 } { 1000 } = \frac { 1 } { 10 }

of V