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Question

Physics Question on thermal properties of matter

An external pressure PP is applied on a cube at 0C0^{\circ}C so that it is equally compressed from all sides.KK is the bulk modulus of the material of the cube and α\alpha is its coefficient of linear expansion.Suppose we want to bring the cube to its original size by heating it. The temperature should be raised by :

A

P3αK\frac{P}{3 \alpha K}

B

PαK\frac{P}{ \alpha K}

C

3αPK\frac{3 \alpha}{P K}

D

3PKα3 P K \alpha

Answer

P3αK\frac{P}{3 \alpha K}

Explanation

Solution

K=ΔP(ΔVV)K = \frac{\Delta P}{\left(-\frac{\Delta V }{V}\right)}
ΔVV=PK\frac{\Delta V}{V} = \frac{P}{K}
V=V0(1+γΔt)\therefore V = V_{0} \left(1 + \gamma\Delta t \right)
ΔVV0=γΔt\frac{\Delta V}{V_{0}} = \gamma\Delta t
PK=γΔt\therefore \frac{P}{K} = \gamma\Delta t
Δt=PγK=P3αK\Rightarrow\Delta t = \frac{P}{\gamma K } =\frac{P}{3 \alpha K}