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Question

Physics Question on physical world

An experiment measures quantities aa, bb and cc, and quantity XX is calculated from X=ab2/c3X= ab^2/c^3. If the percentage error in aa, bb and cc are ±1%\pm 1\%, ±3%\pm 3\% and ±2%\pm 2\%, respectively, then the percentage error in XX will be

A

±13%\pm 13\%

B

±7%\pm 7\%

C

±4%\pm 4\%

D

±1%\pm 1\%

Answer

±13%\pm 13\%

Explanation

Solution

Δxx=Δaa+2Δbb+3Δcc\frac{\Delta x}{x}=\frac{\Delta a}{a}+2\frac{\Delta b}{b}+3\frac{\Delta c}{c}
=±1%+2(±3%)+3(±2%)=\pm1\%+2\left(\pm3\%\right)+3\left(\pm2\%\right)
=±1%±6%±6%=\pm1\%\pm6\%\pm6\%
=±13%=\pm13\%