Question
Question: An excess of \(AgN{{O}_{3}}\) is added to 100ml of a 0.01M solution of dichlorotetraaquachromium(III...
An excess of AgNO3 is added to 100ml of a 0.01M solution of dichlorotetraaquachromium(III)chloride. The number of moles of AgCl precipitate would be:
A. 0.001
B. 0.002
C. 0.003
D.0.01
Explanation
Solution
[Cr(H2O)4Cl2] is a coordination compound. Here the overall charge on the compound is +1. We can calculate the number of moles by the formula:Number of moles=Volume×Molarity
Formula used: Number of moles=Volume×Molarity
Complete step by step answer:
- We can write the formula of given compound as [Cr(H2O)4Cl2]. Now, we will first find the charge on the compound. We know that charge on chromium is +3, charge on water is zero, charge on chlorine is -1. So, we get the overall charge on the compound as: