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Question

Chemistry Question on States of matter

An evacuated glass vessel weighs 50g50 \,g when empty, 144.0g144.0\, g when filled with a liquid of density 0.47gml10.47 \,g \,ml^{-1} and 50.5g50.5\, g when filled with an ideal gas at 760mmHg760 \,mm \,Hg at 300K300\, K. The molar mass of the ideal gas is: (R=0.0821LR= 0.0821\, L atm. K1mol1K^{-1} \,mol^{-1})

A

61.57561.575

B

130.98130.98

C

123.75123.75

D

47.8747.87

Answer

61.57561.575

Explanation

Solution

Weight of empty glass vessel = 50g50\, g
Weight of glass vessel filled with liquid = 144.0g144.0\, g
\therefore Weight of liquid =14450=94g=144-50=94\, g
Density of liquid =0.47gmL1=0.47\, gmL ^{-1}
\therefore Volume of liquid =940.47=200mL=0.2L=\frac{94}{0.47}=200\, mL =0.2\, L
Mass of glass vessel filled with gas =50.5g=50.5\, g
\therefore Mass of gas (m)=50.550=0.5g(m)=50.5-50=0.5\, g
By using ideal gas equation,
pV=mWRTpV =\frac{ m }{ W } RT
where, p=760mm,Hg=1atmp =760\, mm,\, Hg =1\, atm,
V=0.2LT=300KV= 0.2\,L\, T =300\,K
and R=0.0821LR =0.0821\, L atm K1mol1K ^{-1} mol ^{-1}
\therefore Molar mass (M)=mRTpV( M )=\frac{ mRT }{ pV }
=0.5×0.0821×3001×0.2=\frac{0.5 \times 0.0821 \times 300}{1 \times 0.2}
=61.575gmol1=61.575\, g\, mol ^{-1}