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Question: An equilateral triangle is inscribed in the parabola y<sup>2</sup> = 4ax with one vertex at the orig...

An equilateral triangle is inscribed in the parabola y2 = 4ax with one vertex at the origin. The radius of the circum circle of that triangle is

A

2a

B

4a

C

6a

D

8a

Answer

8a

Explanation

Solution

We know that the side of an equilateral triangle inscribed in the parabola y2 = 4ax with one vertex at (0, 0) is 838\sqrt{3}a.

Let R be the circumradius of the triangle then By sine rule 83asin60o\frac{8\sqrt{3}a}{\sin 60^{o}}= 2R

⇒ R = 8a