Question
Question: An equilateral triangle is inscribed in the parabola y<sup>2</sup> = 4ax with one vertex at the orig...
An equilateral triangle is inscribed in the parabola y2 = 4ax with one vertex at the origin. The radius of the circum circle of that triangle is
A
2a
B
4a
C
6a
D
8a
Answer
8a
Explanation
Solution
We know that the side of an equilateral triangle inscribed in the parabola y2 = 4ax with one vertex at (0, 0) is 83a.
Let R be the circumradius of the triangle then By sine rule sin60o83a= 2R
⇒ R = 8a