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Question

Mathematics Question on Three Dimensional Geometry

An equation of the plane passing through the points (3,2,1)(3, 2, -1), (3,4,2)(3, 4, 2) and (7,0,6)(7, 0, 6) is 5x+3y2z=λ5x + 3y - 2z = \lambda, where λ\lambda is

A

2323

B

2121

C

1919

D

2727

Answer

2323

Explanation

Solution

Equation of plane through (3,2,1)(3, 2, -1), (3,4,2)(3, 4, 2) and (7,0,6)(7,0,6) is x3y2z+1 023 427=0\begin{vmatrix}x-3&y-2&z+1\\\ 0&2&3\\\ 4&-2&7\end{vmatrix}=0 i.e., 5x+3y2z=235x + 3y-2z = 23 λ=23\therefore \lambda = 23