Solveeit Logo

Question

Mathematics Question on Distance of a Point from a Plane

An equation of a plane parallel to the plane x2y+2z5=0x-2y+2z-5=0 and at a unit distance from the origin is?

Answer

The correct answer is x2y+2z3=0.x-2y+2z-3=0.
Let an equation of a plane parallel to the plane x2y+2z5=0x−2y+2z−5=0 be x2y+2z+k=0   ...(i)x−2y+2z+k=0\ \ \ ...(i)
Perpendicular distance from O(0,0,0) to (1) is 1
k1+4+4=1\frac{|k|}{\sqrt{1+4+4}}=1
k=3⇒|k|=3
k=+3  or3⇒k=+3\ \ or−3
x2y+2z3=0∴x−2y+2z−3=0