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Question: An engine operating between 150°C and 25°C takes 500 J heat from a higher temperature reservoir if t...

An engine operating between 150°C and 25°C takes 500 J heat from a higher temperature reservoir if there are no frictional losses then work done by engine is

A

147.7J

B

157.75 J

C

165.85J

D

169.95J

Answer

147.7J

Explanation

Solution

T2=150+273=423KT_{2} = 150 + 273 = 423K

T1=25+273=298K\mathbf{T}_{\mathbf{1}}\mathbf{= 25 + 273 = 298K}

q2=500J\mathbf{q}_{\mathbf{2}}\mathbf{= 500J}

wq2=T2−T1T2\frac{\mathbf{w}}{\mathbf{q}_{\mathbf{2}}}\mathbf{=}\frac{\mathbf{T}_{\mathbf{2}}\mathbf{-}\mathbf{T}_{\mathbf{1}}}{\mathbf{T}_{\mathbf{2}}}

w=500[423−298423]=147.7J\mathbf{w = 500}\left\lbrack \frac{\mathbf{423 - 298}}{\mathbf{423}} \right\rbrack\mathbf{= 147.7J}