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Question: An e.m.f. of 12 volts is induced in a given coil when the current in it changes at the rate of 48 am...

An e.m.f. of 12 volts is induced in a given coil when the current in it changes at the rate of 48 amperes per minute. The self inductance of the coil is

A

0.25 henry

B

15 henry

C

1.5 henry

D

9.6 henry

Answer

15 henry

Explanation

Solution

L=edi/dt=1248/60=15HL = \frac { e } { d i / d t } = \frac { 12 } { 48 / 60 } = 15 \mathrm { H }